If k not equal to 0, 1, or -1, is 1/k '>'0?

stmt A. 1/k-1 '>' 0
stmt B. 1/k+1 '>' 0






Let us take statement I - In this, it is given that 1/(k-1) '>'0. This implies that k must be postive and k must be greater than 1. Hence, 1/k is definitely greater than zero. For example, k's value is 2, then 1/(2-1) = 1 which is '>' 0. This implies that 1/2 = 0.5 which si still greater than '0'. Hence, this is sufficient.

Let us take II - It says 1/ (k+1) '> '0 which means that this will satisfy for both positive and negative values of k which are greater than -1. for example, if k is 2, 1/(k+1) is '>'0 and 1/k wll be '>'0. But if k's value is -0.5, it will satisfy the second equation but 1/k will be -2 which is '<'0 and hence, INSUFFICIENT.

Hence, A alone is sufficient to answer this question.