If x does not = -y, is (x-y)/(x+y) > 1?

(1) x > 0
(2) y < 0

(x-y)/(x+y) > 1?
means either:

a) if (x+y) is positive, then the question becomes
x-y > x+y? (direction of inequality sign stays the same as you cross-multiply)
-y > y? (subtract x -- no change to sign)
0 > 2y? (add y -- no change to sign)
0 > y? (divide by 2 -- no change to sign)
=> is y negative?

b) if (x+y) is negative, then the question becomes
x-y <>
same chain of algebra
0 <>
=> is y positive?

Even with the two conditions together, we never know for sure the sign of x+y, so we can't determine which case we're in and therefore which question is being asked. Anwer : E