The sum of first 50 even numbers is 2550 .What is the sum of even numbers from 102 to 200 inclusive?

1)5100
2)7550
3)10100
4)15500
5)20100





One can apply the formula for Sum of series that are in arithmetic progression:
S = n/2 ( 2a + [n-1] *d)

n = 50, a = 102, d= 2....

or

We can break down the problem as

102 + 104 + 106 + ... + 200
=
(100 + 2) + (100 + 4) + (100 + 6) + ... + (100 + 100)
=
(100 + 100 + 100 + ... + 100) + (2 + 4 + 6 + ... + 100)
=
(fifty 100's) + (2550 as given)
=
5000 + 2550
=
7550