If 6xy=x^2y+9y, what is the value of xy

If 6xy=x^2y+9y, what is the value of xy?

1) x= -2
2) x '<' 0




Problem Stem:
6xy =x^2*y +9y
=>6x=y(X^2+9)
=>y(x^2-6x+9)=0
=>y(x^2-3x-3x+9)=0
=>y[x(x-3)-3(x-3)]=0
=>(x-3)(x-3)=0 or y=0
x=3, or y=0

xy=? it depends on the values of x and y.
Stem1:
x=-2, means that x is not equal to 3. So, y=0. and xy=0. SUFF.
Stem2:
x<0, means that x is not equal to 3. So, y=0.
And xy=0. SUFF.
Answer: D