A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

Total ounces of food required by 24 dogs for 7 days = 10*24*7 ------- (1)
Total ounces of dog food in each case = 30*8 ------------ (2)
Therefore, Total 1/Total 2 = 7. Answer is C.