If 0’<’x’<’y, what is the value of

If 0’<’x’<’y, what is the value of (x+y)^2 / (x-y)^2
(1) x^2 + y^2 = 3xy
(2) xy = 3





From 1)
(x+y)^2 = 3xy + 2xyand (x-y)^2 = 3xy -2xy
Noew we can find the reqd ratio...Hence Suff
From 2)
xy = 3It can be expressed as 1/2 * 6 or 3 * 1....we get different ratio's respectively. Hence Insuff.