If 58 is 2 standart deviation below the mean and 98 - 3 standart deviation above the mean, what is mean?



(let us consider m as mean and s as S.D.)
58=m-2s
next if 98 is 3 S.D above the mean,this can be re-written as:
98=m+3s.
Now since we have two equations,solving them we can find out the value of mean and the S.D. The answer that i got is mean is 74 and S.D is 8.

notice one important theme at work here: in problems in which you're given a numerical value of the standard deviation, it's actually completely unimportant that it's called "the standard deviation".