If the sum of five consecutive positive integers is A, then the sum of the next five consecutive integers in terms of A is:
a) A+1
b) A+5
c) A+25
d) 2A
e) 5A
n + n+1 + n+2 + n+3 + n+4 = 5n + 10 = A
n+5 + n+6 + n+7 + n+8 + n+9 = 5n + 35 = A+25
No comments:
Post a Comment