Working, independently X takes 12 hours to finish a certain work. he finishes 2/3 of the work . The rest of the work is finished by Y whose rate is 1/10 th of X. In how much time does Y finsh his work?






Since X finishes 2/3 of the work, the work left over for Y to finish is 1/3.

Since the rate of Y is 1/10th that of X, hence Y will take 10 times the TIME that X takes to finish the same work. Hence Y will finish the same work in
= 12 * 10 = 120 hours

Therefore, If Y takes 120 hours to finish the work of 1 unit, 1/3 units of work will be finished by Y in = (1/3) * 120 = 40 hours.